The following thermochemical equation indicates that 184.8 kJ are released, if two moles of hydrogen react with nitrogen to form ammonia, N₂(g)+ 3 H₂(g)$\rarr$ 2 NH₃(g), $\Delta$H° = -92.38 kJ.

Question

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The given thermochemical equation indicates that 92.38 kJ are released per mole of nitrogen reacting with three moles of hydrogen to form two moles of ammonia, not per two moles of hydrogen.

The Following Thermochemical Equation Indicates That 184 →\rarr→ 2 NH3(g) Δ\DeltaΔ H° = -9238 KJ

The Following Thermochemical Equation Indicates That 184 $\rarr$ 2 NH₃(g) $\Delta$ H° = -9238 KJ