How many grams of NiSO₄7H₂O would be required to prepare 5.00 × 10² mL of a solution that is 0.300 M in NiSO₄(aq)? Hint: Remember to use the correct units when dealing with Molarity.

Question

Quizplus · Accepted Answer

To find the grams of NiSO₄·7H₂O needed, first calculate the moles of NiSO₄ required: 0.300 M × 0.500 L = 0.150 moles. The molar mass of NiSO₄·7H₂O is approximately 262.85 g/mol. Multiply the moles by the molar mass: 0.150 moles × 262.85 g/mol = 39.4275 grams, which rounds to 42.1 grams.

How Many Grams of NiSO47H2O Would Be Required to Prepare

How Many Grams of NiSO₄7H₂O Would Be Required to Prepare