How many mL of 0.300 M NaOH(aq)solution are required to neutralize 1.858 g of KHC₈H₄O₄ (formula weight = 204.22 g/mol)if the reaction is NaOH(aq)+ KHC₈H₄O₄ $\rarr$ NaKC₈H₄O₄(aq)+ H₂O(l)?

Name: How many mL of 0.300 M NaOH(aq)solution are required to neutralize 1.858 g of KHC 8 H 4 O 4 (formula weight = 204.22 g/mol)if the reaction is NaOH(aq)+ KHC 8 H 4 O 4 $\rarr$ NaKC 8 H 4 O 4 (aq)+ H 2 O(l)?
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Question

Quizplus · Accepted Answer

To neutralize 1.858 g of KHC8H4O4, we need 30.3 mL of 0.300 M NaOH(aq) solution.

How Many ML of 0 →\rarr→ NaKC8H4O4(aq)+ H2O(l)? A)30

How Many ML of 0 $\rarr$ NaKC₈H₄O₄(aq)+ H₂O(l)?
A)30