A 0.540 M aqueous solution of sodium tetrafluoroborate (molar mass = 109.79 g mol^-1)contains 14.82 grams of solute in 2.50 × 10² mL of solution.

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The molarity (M) is calculated as moles of solute per liter of solution. 14.82 g of sodium tetrafluoroborate is 0.135 moles (14.82 g / 109.79 g/mol). In 0.250 L (250 mL) of solution, this gives a molarity of 0.540 M (0.135 moles / 0.250 L).

A 0540 M Aqueous Solution of Sodium Tetrafluoroborate (Molar Mass =