For the given process:TiCl₄(g)+ 2Mg(l)→ 2MgCl₂(l)+ Ti(s)the theoretical yield for titanium (Ti(s))was calculated to be 305.6 g. The actual amount of titanium recovered was 285.5 g. What was the percent yield for the process?

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The Answer of For the given process:TiCl₄(g)+ 2Mg(l)→ 2MgCl₂(l)+ Ti(s)the theoretical yield for titanium (Ti(s))was calculated to be 305.6 g. The actual amount of titanium recovered was 285.5 g. What was the percent yield for the process?

For the Given Process:TiCl4(g)+ 2Mg(l)→ 2MgCl2(l)+ Ti(s)the Theoretical Yield for Titanium

For the Given Process:TiCl₄(g)+ 2Mg(l)→ 2MgCl₂(l)+ Ti(s)the Theoretical Yield for Titanium