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A Real World Application of Solubility Products Is Found in Softening

Question 56

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A real world application of solubility products is found in softening "hard water" by removing calcium and magnesium ions present as the sulphate and carbonate salts. We can decrease the amount of Ca2+ in solution by addition of sodium carbonate, a strong electrolyte:Na2CO3 (s) \rightarrow 2 Na+ (aq) + CO32- (aq)By increasing the concentration of carbonate, we tend to drive the solubility equilibrium toward the reactant:CaCO3 (s)  A real world application of solubility products is found in softening  hard water  by removing calcium and magnesium ions present as the sulphate and carbonate salts. We can decrease the amount of Ca<sup>2+</sup> in solution by addition of sodium carbonate, a strong electrolyte:Na<sub>2</sub>CO<sub>3</sub> (s) \rightarrow 2 Na<sup>+ </sup>(aq)<sup> </sup>+ CO<sub>3</sub><sup>2-</sup> (aq)By increasing the concentration of carbonate, we tend to drive the solubility equilibrium toward the reactant:CaCO<sub>3</sub> <sub>(</sub><sub>s</sub><sub>)</sub>   Ca<sup>2+</sup> <sub>(</sub>aq<sub>)</sub> + CO<sub>3</sub><sup>2-</sup> (aq) K<sub>sp</sub> = 4.7 x 10<sup>-9</sup>If the initial [Ca<sup>2+</sup>] = 5.0 x 10<sup>-3</sup><sup> </sup>M, what percent of the [Ca<sup>2+</sup>] will be removed if the carbonate concentration is maintained at 1.0 x 10<sup>-3</sup> M? Ca2+ (aq) + CO32- (aq) Ksp = 4.7 x 10-9If the initial [Ca2+] = 5.0 x 10-3 M, what percent of the [Ca2+] will be removed if the carbonate concentration is maintained at 1.0 x 10-3 M?

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