The equilibrium constant for the following reaction is given:
4 NO₂₍_g) 2 N₂O_(g)+ 3 O_2(g)K₁ = 690What is the value for the equilibrium constant of the reverse reaction?
2 N₂O₍_g)+ 3 O_2(g) 4 NO_2(g) K₂ =?

Question

The equilibrium constant for the following reaction is given:
4 NO₂₍_g)

The equilibrium constant for the following reaction is given: 4 NO<sub>2(</sub><sub>g)</sub> 2 N<sub>2</sub>O<sub>(g)</sub><sub> </sub>+ 3 O<sub>2(g)</sub><sub> </sub>K<sub>1</sub> = 690What is the value for the equilibrium constant of the reverse reaction? 2 N<sub>2</sub>O<sub>(</sub><sub>g)</sub><sub> </sub>+ 3 O<sub>2(g)</sub><sub> </sub> 4 NO<sub>2(g)</sub> K<sub>2</sub> =?

2 N₂O_(g)+ 3 O_2(g)K₁ = 690What is the value for the equilibrium constant of the reverse reaction?
2 N₂O₍_g)+ 3 O_2(g) 4 NO_2(g) K₂ =?

Quizplus · Accepted Answer

The Answer of The equilibrium constant for the following reaction is given: 4 NO₂₍_g) 2 N₂O_(g)+ 3 O_2(g)K₁ = 690What is the value for the equilibrium constant of the reverse reaction? 2 N₂O₍_g)+ 3 O_2(g) 4 NO_2(g) K₂ =?

The Equilibrium Constant for the Following Reaction Is Given