At moderate temperatures, the rate law for the reaction of NO₂ and CO to give CO₂ and NO follows the rate law shown below:rate = k [NO₂]² In which flask will the reaction be faster and how much faster?

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The Answer of At moderate temperatures, the rate law for the reaction of NO₂ and CO to give CO₂ and NO follows the rate law shown below:rate = k [NO₂]² In which flask will the reaction be faster and how much faster?

At Moderate Temperatures, the Rate Law for the Reaction of NO2

At Moderate Temperatures, the Rate Law for the Reaction of NO₂