Acetone CH3COCH3 boils at a significantly higher temperature than 2-methylpropane isobutene
A) because dipole-dipole forces are always greater than dispersion forces.
B) because the molecular mass of acetone is slightly less than that of 2-methylpropane.
C) because the density of acetone is greater than that of 2-methylpropane.
D) because the attractive dispersion forces in 2-methylpropane are weaker than those in acetone.
E) because the attractive dispersion forces in 2-methylpropane are weaker than the dipole forces in acetone.
Correct Answer:
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