How much water must be added when 125 mL of a 2.00 M solution of HCl is diluted to a final concentration of 0.400 M?

Question

Quizplus · Accepted Answer

To dilute a solution, the formula $C_1V_1 = C_2V_2$ is used, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Plugging in the given values: $2.00 \, \text{M} \times 125 \, \text{mL} = 0.400 \, \text{M} \times V_2$. Solving for $V_2$ gives $V_2 = 625 \, \text{mL}$. To find the amount of water added, subtract the initial volume from the final volume: $625 \, \text{mL} - 125 \, \text{mL} = 500 \, \text{mL}$.

How Much Water Must Be Added When 125 ML of a 2.00