If a scuba diver's lungs have a normal capacity of 4.9 L at sea level (1.0 atm), what would be the volume of her lungs if the pressure at a depth of 50 ft is 975 mmHg?

Question

Quizplus · Accepted Answer

Using Boyle's Law (P1V1 = P2V2), we can find the volume of the lungs at the new pressure. First, convert the pressure at 50 ft to atm (975 mmHg * 1 atm/760 mmHg = 1.28 atm). Then, solve for V2: V2 = (P1V1)/P2 = (1.0 atm * 4.9 L) / 1.28 atm = 3.8 L.

If a Scuba Diver's Lungs Have a Normal Capacity of 4.9