Suppose you stir 100 g of water and do 419 J of work on the system. Assuming no leakage of energy, what will the resulting change in water temperature be? A) -1^o C B) -1^o F C) +1^o F D) + 1^o C

Question

Quizplus · Accepted Answer

The energy required to change the temperature of 1 gram of water by 1°C (specific heat capacity of water) is 4.186 J. Therefore, 419 J of energy will increase the temperature of 100 g of water by $ \frac{419 \, \text{J}}{100 \, \text{g} \times 4.186 \, \text{J/g°C}} = 1 \, \text{°C} $.

Suppose You Stir 100 G of Water and Do 419