Suppose you do 1000 J of work on a 5 kg object, and all the work went into lifting it above the ground. How high above the ground will the object be when all the work has been done?
A) 100 m
B) 5 m
C) 20 m
D) 1 m

Question

Quizplus · Accepted Answer

The work done on the object is equal to the change in gravitational potential energy, which is given by the formula $ \Delta U = mgh $, where $ \Delta U $ is the change in potential energy, $ m $ is the mass of the object, $ g $ is the acceleration due to gravity (approximately $ 9.8 \, \text{m/s}^2 $), and $ h $ is the height. Rearranging the formula to solve for $ h $, we get $ h = \frac{\Delta U}{mg} $. Substituting the given values, $ h = \frac{1000 \, \text{J}}{5 \, \text{kg} \cdot 9.8 \, \text{m/s}^2} \approx 20 \, \text{m} $.

Suppose You Do 1000 J of Work on a 5