Find the surface area of the part of the sphere x 2 + y 2 + z 2 = 36 inside the cylinder and above the xy-plane.

The Answer of Find the surface area of the part of the sphere x 2 + y 2 + z 2 = 36 inside the cylinder and above the xy-plane.

Find the surface area of the part of the sphere x 2 + y 2 + z 2 = 36 inside the cylinder and above the xy-plane.

The Answer of Find the surface area of the part of the sphere x 2 + y 2 + z 2 = 36 inside the cylinder and above the xy-plane.

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Find the Surface Area of the Part of the Sphere $\pi$

Question 89

Multiple Choice

Find the surface area of the part of the sphere x² + y² + z² = 36 inside the cylinder $Find the surface area of the part of the sphere x<sup>2</sup> + y<sup>2</sup> + z<sup>2</sup> = 36 inside the cylinder and above the xy-plane. A) 36 \pi - 36 square units B) 36 \pi - 72 square units C) 72 \pi - 72 square units D) 72 \pi - 36 square units E) 36 \pi square units$ and above the xy-plane.