Situation A proton (rest energy = 938 MeV) has a speed of 0.80 c. -In Situation above, the momentum of the proton in kg ? m/s is closest to: A) 4.0 × 10^-19 B) 4.4 × 10^-19 C) 5.0 × 10^-19 D) 5.8 × 10^-19 E) 6.7 × 10^-19

Question

Quizplus · Accepted Answer

The relativistic momentum p is given by p = γmv, where γ = 1/√(1-v²/c²). For v = 0.80c, γ ≈ 1.667. The rest mass m of the proton is 938 MeV/c² ≈ 1.67 × 10^-27 kg. Thus, p ≈ 1.667 × 1.67 × 10^-27 kg × 0.80 × 3 × 10^8 m/s ≈ 6.7 × 10^-19 kg·m/s.

Situation A Proton (Rest Energy = 938 MeV) Has a Speed