A ?⁺ and ?^- at rest annihilate to produce two gamma rays that fly in the opposite directions. What is the wavelength of each gamma ray? The rest energy of a muon is 106 MeV and
H = 6.63 × 10^-34 J·s.

Question

Quizplus · Accepted Answer

The correct answer is A.The total energy of the two gamma rays is equal to the rest energy of the muon, which is 106 MeV. The wavelength of each gamma ray is given by the equation:$$\lambda = \frac{hc}{E}$$where h is Planck's constant, c is the speed of light, and E is the energy of the gamma ray.Substituting the given values into the equation, we get:$$\lambda = \frac{(6.63 	imes 10^{-34} 	ext{ J$\cdot$s})(3 	imes 10^8 	ext{ m/s})}{106 	imes 1.6 	imes 10^{-13} 	ext{ J}} = 1.17 	imes 10^{-14} 	ext{ m}$$

A ?+ and ?- at Rest Annihilate to Produce Two

A ?⁺ and ?^- at Rest Annihilate to Produce Two