In a sample of 500 students, 80% prefer online resources versus printed materials. The standard error for the sample proportion is
A) 0.002
B) 0.018
C) 0.014
D) 0.040

Question

Quizplus · Accepted Answer

The standard error for the sample proportion is calculated using the formula $\sqrt{\frac{p(1-p)}{n}}$, where $p$ is the sample proportion and $n$ is the sample size. Here, $p = 0.80$ and $n = 500$, so the calculation is $\sqrt{\frac{0.80(1-0.80)}{500}} = \sqrt{\frac{0.80(0.20)}{500}} = \sqrt{\frac{0.16}{500}} = \sqrt{0.00032} = 0.0179$, which rounds to 0.018.

In a Sample of 500 Students, 80% Prefer Online Resources