Solve the problem. Round your answer, if appropriate.
-Water is being drained from a container which has the shape of an inverted right circular cone. The container has a radius of 3.00 inches at the top and a height of 5.00 inches. At the instant when the water in the container is 3.00 inches deep, the surface level is falling at a rate of 1.7 in./sec. Find the rate at which water is being drained from the container.

Question

Quizplus · Accepted Answer

The volume of a cone is given by V = (1/3)πr²h. Using similar triangles, when the water is 3 inches deep, the radius is (3/5) * 3 = 1.8 inches. The rate of change of volume dV/dt can be found using the chain rule: dV/dt = (dV/dh)(dh/dt). Substituting the values and solving gives approximately 17.3 in.³/s.

Solve the Problem. Round Your Answer, If Appropriate