A solution is prepared by dissolving 1.0 x 10^-4 moles of HOBr in water and diluting to 1.00 L. What is the pH of this solution? (HOBr: K_a = 2 x 10^-9)

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Quizplus · Accepted Answer

The concentration of HOBr is 1.0 x 10^-4 M. Using the formula for weak acid dissociation, [H+] = √(Ka * [HOBr]), we find [H+] = √(2 x 10^-9 * 1.0 x 10^-4) = √(2 x 10^-13) = 1.41 x 10^-7. The pH is -log(1.41 x 10^-7) ≈ 6.3.

A Solution Is Prepared by Dissolving 1