How many $\textbf{ pairs }$ of nonbonding electrons are in the valence shell of the iodine atom in the ICl₄^- ion?

Question

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Iodine (I) in the ICl4^- ion has 7 valence electrons. When forming the ion, iodine shares one electron with each of the four chlorine atoms and has one extra electron due to the negative charge, making a total of 8 electrons in its valence shell. These are arranged as four pairs, with two pairs involved in bonding with chlorine atoms and two pairs remaining as nonbonding (lone pairs). Therefore, there are 2 pairs of nonbonding electrons.

How Many pairs \textbf{ pairs } pairs

How Many $\textbf{ pairs }$