A helium-neon laser emits light with a wavelength of 6328 Å. What is the energy of a 6328 Å photon in joules?

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the equation $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant ($6.626 \times 10^{-34}$ Js), $c$ is the speed of light ($3.00 \times 10^8$ m/s), and $\lambda$ is the wavelength in meters. Converting 6328 Å to meters (1 Å = $1 \times 10^{-10}$ m), we get $\lambda = 6328 \times 10^{-10}$ m. Plugging these values into the equation gives $E = \frac{(6.626 \times 10^{-34})(3.00 \times 10^8)}{6328 \times 10^{-10}}$ J, which calculates to approximately $3.139 \times 10^{-19}$ J.

A Helium-Neon Laser Emits Light with a Wavelength of 6328