If 0.50 moles of PbS are combined with 0.50 moles of O₂, how many moles of PbO can be produced by the following reaction?
2 PbS(s) + 3 O₂(g) $\rightarrow$ 2 PbO(s) + 2 SO₂(g)

Question

If 0.50 moles of PbS are combined with 0.50 moles of O₂, how many moles of PbO can be produced by the following reaction? 2 PbS(s) + 3 O₂(g) $\rightarrow$ 2 PbO(s) + 2 SO₂(g)

Quizplus · Accepted Answer

The reaction requires 3 moles of O2 for every 2 moles of PbS. With 0.50 moles of each reactant, O2 is the limiting reactant, allowing for only 0.33 moles of PbO to be produced.

If 050 Moles of PbS Are Combined with 0 →\rightarrow→ 2 PbO(s) + 2 SO2(g) A) 0

If 050 Moles of PbS Are Combined with 0 $\rightarrow$ 2 PbO(s) + 2 SO₂(g)
A) 0