A horizontal metal bar that is 2.0 m long rotates at a constant angular velocity of 2.0 rad/s about a vertical axis through one of its ends while in a constant magnetic field of 5 × 10^-5 T. If the magnetic field vector points straight down, what emf is induced between the two ends of the bar? A) 2.0 × 10^-⁴ V B) 3.6 × 10^-³ V C) 5.6 × 10^-³ V D) 7.0 × 10^-⁴ V E) 1.6 × 10^-⁴ V

Question

Quizplus · Accepted Answer

The magnitude of the induced emf is given by:emf = Blvwhere:B is the magnetic field strengthl is the length of the barv is the velocity of the barPlugging in the given values, we get:emf = (5 × 10^-5 T)(2.0 m)(2.0 rad/s) = 2.0 × 10^-4 VTherefore, the correct choice is A.

A Horizontal Metal Bar That Is 2