The natural frequencies for a stretched string of length L, and wave speed v, are Nv/(2L) where N equals
A) 0, 1, 3, 5, ...
B) 1, 3, 4, 5, ...
C) 1, 2, 3, 4, ...
D) 2, 4, 6, 8, ...
E) 0, 1, 2, 3, ...

Question

Quizplus · Accepted Answer

The natural frequencies of a stretched string are determined by the harmonics of the string, which are integer multiples of the fundamental frequency. This means N can be any positive integer, including 1, 2, 3, 4, etc., making option C correct.

The Natural Frequencies for a Stretched String of Length L