A string of linear density 1.5 g/m is under a tension of 20. N. What should its length be if its fundamental resonance frequency is 220. Hz?
A) 0.26 m
B) 0.96 m
C) 43. cm
D) 2.1 m
E) 1.1 m

Question

Quizplus · Accepted Answer

The fundamental resonance frequency of a string is given by:f = (1/2L) * sqrt(T/μ)where:f is the frequencyL is the length of the stringT is the tension in the stringμ is the linear density of the stringPlugging in the given values, we get:220 Hz = (1/2L) * sqrt(20 N / 1.5 g/m)Solving for L, we get:L = 0.26 m

A String of Linear Density 1