A spring is characterized by a spring constant of 60. N/m. How much potential energy does it store, when stretched by 1.0 cm?

Question

Quizplus · Accepted Answer

The potential energy stored in a spring is given by the formula $PE = \frac{1}{2} k x^2$, where $k$ is the spring constant and $x$ is the displacement in meters. Converting 1.0 cm to meters gives 0.01 m. Substituting the values, $PE = \frac{1}{2} \times 60 \times (0.01)^2 = 0.003$ J.

A Spring Is Characterized by a Spring Constant of 60 μ\muμ

A Spring Is Characterized by a Spring Constant of 60 $\mu$