An elevator weighing 10,000. N is supported by a steel cable. Determine the tension in the cable when the elevator is accelerated upward at 3.0 m/s². (g = 9.8 m/s²) A) 11. kN B) 40. kN C) 13. kN D) 10. kN E) 7.0 kN

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Quizplus · Accepted Answer

The tension in the cable can be found using the formula $T = mg + ma$, where $m$ is the mass of the elevator, $g$ is the acceleration due to gravity, and $a$ is the acceleration of the elevator. Given that the weight of the elevator ($W$) is 10,000 N and $g = 9.8 \, \text{m/s}^2$, we first find the mass $m = \frac{W}{g} = \frac{10,000}{9.8} \approx 1020.4 \, \text{kg}$. With $a = 3.0 \, \text{m/s}^2$, the tension $T = 1020.4 \times 9.8 + 1020.4 \times 3.0 \approx 13,000 \, \text{N}$ or 13 kN.

An Elevator Weighing 10,000