A car starts from rest and accelerates uniformly at 3 m/s². A second car starts from rest 6 s later at the same point and accelerates uniformly at 5 m/ s². How long does it take the second car to overtake the first car?

Question

Quizplus · Accepted Answer

Explanation:The first car travels for 6 s before the second car starts. In this time, it travels a distance of 0.5 * 3 * 6^2 = 54 m.The second car travels for a time t before it overtakes the first car. In this time, it travels a distance of 0.5 * 5 * t^2.When the second car overtakes the first car, the two cars have traveled the same distance. Therefore, we can set the two distances equal to each other and solve for t:0.5 * 5 * t^2 = 54t^2 = 21.6t = 4.6 sThe second car overtakes the first car 6 s after the first car starts, so the total time taken is 6 + 4.6 = 10.6 s.

A Car Starts from Rest and Accelerates Uniformly at 3