In the preceding problem, the erroneous answer generated would be corrected by:
A) converting both BCD code groups to straight binary form and subtracting 0110 from the least significant code group.
B) adding 0110 to the least significant code group.
C) adding 0110 to both the most and least significant BCD code groups.
D) adding 0110 to the most significant code group.

Question

Quizplus · Accepted Answer

When dealing with BCD (Binary-Coded Decimal) arithmetic and an erroneous result occurs due to a sum exceeding 9 (a condition not allowed in BCD since each nibble must represent a decimal digit from 0 to 9), the standard correction method is to add 6 (0110 in binary) to the erroneous digit. This adjustment is known as the "end-around carry" or "nibble correction" and is applied to the least significant digit that has exceeded the BCD limit, hence option B is correct.

In the Preceding Problem, the Erroneous Answer Generated Would Be