To be dimensionally consistent, velocity $[\mathrm{L} / \mathrm{T}]$, acceleration $\left[\mathrm{L} / \mathrm{T}^{2}\right]$ and time $[\mathrm{T}]$ must be related as follows.
A) velocity $=$ acceleration $2 \times$ time $^{2}$
B) velocity $=$ acceleration $2 \times$ time
C) velocity $=$ acceleration $\times$ time $^{2}$
D) velocity $=$ acceleration $\times$ time

Question

Quizplus · Accepted Answer

The dimension of velocity $[\mathrm{L} / \mathrm{T}]$ can be obtained by multiplying the dimension of acceleration $\left[\mathrm{L} / \mathrm{T}^{2}\right]$ by the dimension of time $[\mathrm{T}]$, resulting in $\left[\mathrm{L} / \mathrm{T}^{2}\right] \times [\mathrm{T}] = [\mathrm{L} / \mathrm{T}]$, which matches the dimension of velocity.

To Be Dimensionally Consistent, Velocity [L/T][\mathrm{L} / \mathrm{T}][L/T] , Acceleration [L/T2]\left[\mathrm{L} / \mathrm{T}^{2}\right][L/T2]

To Be Dimensionally Consistent, Velocity $[\mathrm{L} / \mathrm{T}]$ , Acceleration $\left[\mathrm{L} / \mathrm{T}^{2}\right]$