A copper ball with a diameter of $5.00 \mathrm{~cm}$ is subjected to a pressure of $2.50 \times 10^{6} \mathrm{~Pa}$. The bulk modulus for copper is $1.40 \times 10^{11} \mathrm{~N} / \mathrm{m}^{2}$. What is the magnitude of the volume strain?
A) $2.94 \times 10-5$
B) $1.79 \times 10^{-5}$
C) $3.21 \times 10^{-5}$
D) $2.55 \times 10^{-5}$
E) $2.09 \times 10^{-5}$

Question

Quizplus · Accepted Answer

The volume strain is calculated using the formula $\frac{\Delta V}{V} = \frac{P}{B}$, where $P$ is the pressure applied, and $B$ is the bulk modulus. Substituting the given values, $\frac{\Delta V}{V} = \frac{2.50 \times 10^{6}}{1.40 \times 10^{11}} = 1.79 \times 10^{-5}$.

A Copper Ball with a Diameter Of 5.00 cm5.00 \mathrm{~cm}5.00 cm Is Subjected to a Pressure Of

A Copper Ball with a Diameter Of $5.00 \mathrm{~cm}$ Is Subjected to a Pressure Of