Abrass rod is $25.0 \mathrm{~cm}$ long at a temperature of $20.0^{\circ} \mathrm{C}$. The coefficient of linear expansion of brass is $19.0 \times$ $10^{-6} /{ }^{\circ} \mathrm{C}$. If the temperature changes to $25^{\circ} \mathrm{C}$, then the increase in length of the brass rod is
A) $2.38 \times 10^{-5} \mathrm{~m}$.
B) $3.03 \times 10^{-5} \mathrm{~m}$.
C) $4.01 \times 10^{-5} \mathrm{~m}$.
D) $1.65 \times 10^{-5} \mathrm{~m}$.
E) $3.72 \times 10^{-5} \mathrm{~m}$.

Question

Quizplus · Accepted Answer

The change in length of the brass rod is given by:$$\Delta L = \alpha L_i \Delta T$$where:* $\alpha$ is the coefficient of linear expansion* $L_i$ is the initial length of the rod* $\Delta T$ is the change in temperatureSubstituting the given values into the equation, we get:$$\Delta L = (19.0 \times 10^{-6} /{ }^{\circ} \mathrm{C})(25.0 \mathrm{~cm})(5^{\circ} \mathrm{C}) = 2.38 \times 10^{-5} \mathrm{~m}$$Therefore, the increase in length of the brass rod is $2.38 \times 10^{-5} \mathrm{~m}$.

Abrass Rod Is 25.0 cm25.0 \mathrm{~cm}25.0 cm Long at a Temperature Of 20.0∘C20.0^{\circ} \mathrm{C}20.0∘C

Abrass Rod Is $25.0 \mathrm{~cm}$ Long at a Temperature Of $20.0^{\circ} \mathrm{C}$