The outer surface of a wood-burning stove in a cabin is at a temperature of $150^{\circ} \mathrm{C}$. What is the wavelength at which the blackbody radiation is a maximum?

Question

Quizplus · Accepted Answer

The wavelength of maximum emission for a blackbody is given by Wien's displacement law: $\lambda_{\text{max}} = \frac{b}{T}$, where $b = 2898 \, \mu \mathrm{m} \cdot \mathrm{K}$. Converting $150^{\circ} \mathrm{C}$ to Kelvin gives $423 \, \mathrm{K}$. Thus, $\lambda_{\text{max}} = \frac{2898}{423} \approx 6.85 \, \mu \mathrm{m}$.

The Outer Surface of a Wood-Burning Stove in a Cabin 150∘C150^{\circ} \mathrm{C}150∘C

The Outer Surface of a Wood-Burning Stove in a Cabin $150^{\circ} \mathrm{C}$