$1.00 \mathrm{~mol}$ of oxygen gas $\left(\mathrm{O}_{2}\right)$ is heated at constant pressure of $1.00 \mathrm{~atm}$ from $10.0^{\circ} \mathrm{C}$ to $25.0^{\circ} \mathrm{C}$ . From the first law, calculate the change of internal energy of the gas in this process.

Question

1.00 \mathrm{~mol}

of oxygen gas

\left(\mathrm{O}_{2}\right)

is heated at constant pressure of

1.00 \mathrm{~atm}

from

10.0^{\circ} \mathrm{C}

to

25.0^{\circ} \mathrm{C}

. From the first law, calculate the change of internal energy of the gas in this process.

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The Answer of 
 $1.00 \mathrm{~mol}$ of oxygen gas $\left(\mathrm{O}_{2}\right)$ is heated at constant pressure of $1.00 \mathrm{~atm}$ from $10.0^{\circ} \mathrm{C}$ to $25.0^{\circ} \mathrm{C}$. From the first law, calculate the change of internal energy of the gas in this process.

1.00 mol1.00 \mathrm{~mol}1.00 mol Of Oxygen Gas (O2)\left(\mathrm{O}_{2}\right)(O2​) Is Heated at Constant Pressure Of

$1.00 \mathrm{~mol}$ Of Oxygen Gas $\left(\mathrm{O}_{2}\right)$ Is Heated at Constant Pressure Of