One mole of an ideal gas freely expands from 1.00 liter to 2.00 liters. The change in entropy of the gas in the expansion is

Question

Quizplus · Accepted Answer

The change in entropy ($\Delta S$) for an ideal gas during a free expansion can be calculated using the formula $\Delta S = nR\ln\frac{V_f}{V_i}$, where $n$ is the number of moles, $R$ is the gas constant (8.314 J/mol·K), $V_f$ is the final volume, and $V_i$ is the initial volume. Substituting the given values, $\Delta S = 1 \times 8.314 \times \ln\frac{2.00}{1.00} = 8.314 \times \ln(2) \approx 5.76 \mathrm{~J/K}$, which is closest to choice A, $5.80 \mathrm{~J/K}$.

One Mole of an Ideal Gas Freely Expands from 1 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}5.80 J/K

One Mole of an Ideal Gas Freely Expands from 1 $5.80 \mathrm{~J} / \mathrm{K}$