If A $0.20 \mathrm{pF}$ Capacitor Has a Voltage Of $40 \mathrm{mV}$ , How Many More Electrons Are on the Negative Plate

If a $0.20 \mathrm{pF}$ capacitor has a voltage of $40 \mathrm{mV}$ , how many more electrons are on the negative plate than on the positive plate?

A) $5.0 \times 104$
B) $8.0 \times 1014$
C) $4.0 \times 10^{3}$
D) $1.0 \times 10^{5}$
E) none, the electrons are in equal numbers on the plates