Two capacitors of values $6.00 \mathrm{mF}$ and $9.00 \mathrm{mF}$ are connected in series to a $30.0 \mathrm{~V}$ power supply. What is the resulting charge on the $6.00 \mathrm{mF}$ capacitor?
A) $180 \mathrm{mC}$
B) $200 \mathrm{mC}$
C) $108 \mathrm{mC}$
D) $270 \mathrm{mC}$
E) $90.0 \mathrm{mC}$

Question

Quizplus · Accepted Answer

When capacitors are connected in series, the charge on each capacitor is the same. The equivalent capacitance $C_{eq}$ for capacitors in series is given by $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2}$, where $C_1$ and $C_2$ are the capacitances of the individual capacitors. For the given capacitors, $C_{eq} = \frac{1}{\frac{1}{6.00} + \frac{1}{9.00}} = 3.60 \mathrm{mF}$. The charge $Q$ is given by $Q = C_{eq}V$, where $V$ is the voltage. Thus, $Q = 3.60 \mathrm{mF} \times 30.0 \mathrm{V} = 108 \mathrm{mC}$.

Two Capacitors of Values 6.00mF6.00 \mathrm{mF}6.00mF And 9.00mF9.00 \mathrm{mF}9.00mF Are Connected in Series to A

Two Capacitors of Values $6.00 \mathrm{mF}$ And $9.00 \mathrm{mF}$ Are Connected in Series to A