In vacuum, the components of an $\mathrm{EM}$ wave are $\mathrm{E}_{\mathrm{y}}=(50 \mathrm{~V} / \mathrm{m}) \cos \left[\left(5.0 \mathrm{~m}^{-1}\right) \mathrm{x}+\omega \mathrm{t}\right], \mathrm{E}_{\mathrm{x}}=0$, and $\mathrm{E}_{\mathrm{Z}}=0$. What is the amplitude of the magnetic field for this wave?
A) $1.50 \times 10^{-6} \mathrm{~T}$
B) $1.67 \times 10^{-7} \mathrm{~T}$
C) $2.00 \times 10^{-7} \mathrm{~T}$
D) $5.00 \times 10^{-7} \mathrm{~T}$
E) $1.33 \times 10^{-6} \mathrm{~T}$

Question

Quizplus · Accepted Answer

The amplitude of the magnetic field $B$ in an electromagnetic wave is related to the amplitude of the electric field $E$ by the equation $B = \frac{E}{c}$, where $c$ is the speed of light in vacuum ($3.00 \times 10^8 \, \text{m/s}$). Given $E = 50 \, \text{V/m}$, $B = \frac{50}{3.00 \times 10^8} = 1.67 \times 10^{-7} \, \text{T}$.

In Vacuum, the Components of An EM\mathrm{EM}EM Wave Are , And EZ=0\mathrm{E}_{\mathrm{Z}}=0EZ​=0

In Vacuum, the Components of An $\mathrm{EM}$ Wave Are , And $\mathrm{E}_{\mathrm{Z}}=0$