When Light Ray Goes Through Two Thick Rectangular Slabs of Glass

When light ray goes through two thick rectangular slabs of glass, each of the same uniform thickness. The first slab has index of refraction $\mathrm{n}_{1}$ and the second $\mathrm{n}_{2}$ . If $\mathrm{n}_{1}<\mathrm{n}_{2}$ . How does the original angle of incidence $\theta_{\mathrm{i}}$ into the first slab compare to the final angle of refraction $\theta_{\mathrm{f}}$ where the ray leaves the second slab going back into air?

A) $\theta_{\mathrm{i}}=\left(\mathrm{n}_{1} / \mathrm{n}_{2}\right) \theta_{\mathrm{f}}$
B) $\theta_{\mathrm{i}}<\theta_{\mathrm{f}}$
C) $\theta_{\mathrm{i}}>\theta_{\mathrm{f}}$
D) $\theta_{\mathrm{i}}=\theta_{\mathrm{f}}$
E) more information is needed