A $50.0 \mathrm{~mm}$ lens is used to take a picture of an object $1.30 \mathrm{~m}$ tall located $4.00 \mathrm{~m}$ away. What is the height of the image on the film?
A) $16.5 \mathrm{~mm}$
B) $21.0 \mathrm{~mm}$
C) $10.5 \mathrm{~mm}$
D) $12.0 \mathrm{~mm}$
E) $9.20 \mathrm{~mm}$

Question

Quizplus · Accepted Answer

The height of the image can be calculated using the lens formula and magnification. The magnification (m) is given by the ratio of the image height (h') to the object height (h), and also equals the ratio of the image distance (v) to the object distance (u). Given that the object distance (u) is $4.00 \mathrm{~m}$ and the focal length (f) of the lens is $50.0 \mathrm{~mm} = 0.050 \mathrm{~m}$, we can first find the image distance (v) using the lens equation $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$. Solving for v gives us the image distance. Then, using the magnification equation $m = \frac{h'}{h} = \frac{v}{u}$, we can solve for the image height (h'). The correct calculation leads to an image height of approximately $16.5 \mathrm{~mm}$, making option A correct.

A 50.0 mm50.0 \mathrm{~mm}50.0 mm Lens Is Used to Take a Picture of an Object

A $50.0 \mathrm{~mm}$ Lens Is Used to Take a Picture of an Object