A grating with 8000 slits over $2.54 \mathrm{~cm}$ is illuminated by light of a wavelength of $546 \mathrm{~nm}$. What is the angle for the third-order maximum?
A) $10.5^{\circ}$
B) $15.1^{\circ}$
C) $31.1^{\circ}$
D) $26.3^{\circ}$

Question

Quizplus · Accepted Answer

The grating equation is $d \sin \theta = m \lambda$, where $d$ is the distance between slits, $\theta$ is the angle, $m$ is the order, and $\lambda$ is the wavelength. Calculate $d = \frac{2.54 \, \text{cm}}{8000}$, convert to meters, and solve for $\theta$ for $m = 3$.

A Grating with 8000 Slits Over 2.54 cm2.54 \mathrm{~cm}2.54 cm Is Illuminated by Light of a Wavelength Of

A Grating with 8000 Slits Over $2.54 \mathrm{~cm}$ Is Illuminated by Light of a Wavelength Of