In a Compton scattering experiment, the scattered photon has a wavelength of $6.55 \mathrm{pm}$. If the scattering angle is $50^{\circ}$, what was the wavelength of the incident photon?
A) $0.868 \mathrm{pm}$
B) $7.42 \mathrm{pm}$
C) $3.28 \mathrm{pm}$
D) $5.68 \mathrm{pm}$
E) $2.43 \mathrm{pm}$

Question

Quizplus · Accepted Answer

The Compton wavelength shift formula is $\Delta \lambda = \frac{h}{m_e c} (1 - \cos \theta)$. Given $\lambda' = 6.55 \mathrm{pm}$ and $\theta = 50^{\circ}$, solve for $\lambda$. The shift $\Delta \lambda$ is approximately $0.87 \mathrm{pm}$, so $\lambda = 6.55 \mathrm{pm} - 0.87 \mathrm{pm} = 5.68 \mathrm{pm}$.

In a Compton Scattering Experiment, the Scattered Photon Has a Wavelength