What is the ratio of radii of the nuclides $\mathrm{U}_{92}^{238}$ and $\mathrm{Ca}_{20}{ }_{20}$ ?

Name: What is the ratio of radii of the nuclides $\mathrm{U}_{92}^{238}$ and $\mathrm{Ca}_{20}{ }_{20}$ ?
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The radius of a nucleus is proportional to the cube root of its mass number (A). For $\mathrm{U}_{92}^{238}$, A = 238, and for $\mathrm{Ca}_{20}^{40}$, A = 40. The ratio of their radii is $(238/40)^{1/3} \approx 1.81$.

What Is the Ratio of Radii of the Nuclides U92238\mathrm{U}_{92}^{238}U92238​ And Ca2020\mathrm{Ca}_{20}{ }_{20}Ca20​20​

What Is the Ratio of Radii of the Nuclides $\mathrm{U}_{92}^{238}$ And $\mathrm{Ca}_{20}{ }_{20}$