The gravitational field at the Earth due to the Moon is about ( $\mathrm{G}=6.67 \times 10^{-11} \mathrm{~N} \mathrm{~m}^{2} / \mathrm{kg}^{2}$, the mass of the Moon is $7.35 \times 10^{22} \mathrm{~kg}$, and the distance to the Moon is $3.85 \times 10^{8} \mathrm{~m}$ )
A) $7.50 \times 10-5 \mathrm{~N} / \mathrm{kg}$ away from the Moon.
B) $2.90 \times 10-5 \mathrm{~N} / \mathrm{kg}$ away from the Moon.
C) $4.01 \times 10^{-5} \mathrm{~N} / \mathrm{kg}$ toward the Moon.
D) $3.31 \times 10^{-5} \mathrm{~N} / \mathrm{kg}$ away from the Moon.
E) $3.31 \times 10^{-5} \mathrm{~N} / \mathrm{kg}$ toward the Moon.

Question

Quizplus · Accepted Answer

The gravitational field due to the Moon can be calculated using the formula $g = \frac{G \cdot M}{r^2}$, where $G$ is the gravitational constant, $M$ is the mass of the Moon, and $r$ is the distance to the Moon. Substituting the given values, $g = \frac{6.67 \times 10^{-11} \cdot 7.35 \times 10^{22}}{(3.85 \times 10^{8})^2}$ results in approximately $3.31 \times 10^{-5} \mathrm{~N} / \mathrm{kg}$, and since gravity attracts, it is toward the Moon.

The Gravitational Field at the Earth Due to the Moon G=6.67×10−11 N m2/kg2\mathrm{G}=6.67 \times 10^{-11} \mathrm{~N} \mathrm{~m}^{2} / \mathrm{kg}^{2}G=6.67×10−11 N m2/kg2

The Gravitational Field at the Earth Due to the Moon $\mathrm{G}=6.67 \times 10^{-11} \mathrm{~N} \mathrm{~m}^{2} / \mathrm{kg}^{2}$