The Crab Pulsar is a neutron star, rotating with a period of about $33.085 \mathrm{~ms}$. It is estimated to have an equatorial radius of $15 \mathrm{~km}$, about average for a neutron star. The pulsar is slowing in its rotation so that it is expected to come to rest $9.5 \times 10^{10} \mathrm{~s}$ in the future. What is the magnitude of the average angular acceleration in this situation?
A) $3.2 \times 10^{-10} \mathrm{rad} / \mathrm{s}^{2}$
B) $2.0 \times 10^{-9} \mathrm{rad} / \mathrm{s}^{2}$
C) $3.0 \times 10^{-5} \mathrm{rad} / \mathrm{s}^{2}$
D) $7.6 \times 10^{-7} \mathrm{rad} / \mathrm{s}^{2}$
E) $4.8 \times 10^{-6} \mathrm{rad} / \mathrm{s}^{2}$

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The Answer of  The Crab Pulsar is a neutron star, rotating with a period of about $33.085 \mathrm{~ms}$. It is estimated to have an equatorial radius of $15 \mathrm{~km}$, about average for a neutron star. The pulsar is slowing in its rotation so that it is expected to come to rest $9.5 \times 10^{10} \mathrm{~s}$ in the future. What is the magnitude of the average angular acceleration in this situation?
A) $3.2 \times 10^{-10} \mathrm{rad} / \mathrm{s}^{2}$
B) $2.0 \times 10^{-9} \mathrm{rad} / \mathrm{s}^{2}$
C) $3.0 \times 10^{-5} \mathrm{rad} / \mathrm{s}^{2}$
D) $7.6 \times 10^{-7} \mathrm{rad} / \mathrm{s}^{2}$
E) $4.8 \times 10^{-6} \mathrm{rad} / \mathrm{s}^{2}$

The Crab Pulsar Is a Neutron Star, Rotating with a Period