A spring is stretched from $0.500 \mathrm{~m}$ to $0.800 \mathrm{~m}$. Assume the unstretched position is $0.00 \mathrm{~m}$. If the spring constant of the spring is $10.0 \mathrm{~N} / \mathrm{m}$, what is the work done on the spring?

Question

Quizplus · Accepted Answer

The work done on the spring can be calculated using the formula for the work done in stretching (or compressing) a spring: $W = \frac{1}{2} k x^2$, where $k$ is the spring constant and $x$ is the change in length of the spring. Here, $x = 0.800 \, \mathrm{m} - 0.500 \, \mathrm{m} = 0.300 \, \mathrm{m}$, and $k = 10.0 \, \mathrm{N/m}$. Thus, $W = \frac{1}{2} \times 10.0 \, \mathrm{N/m} \times (0.300 \, \mathrm{m})^2 = 0.5 \times 10.0 \times 0.09 = 1.95 \, \mathrm{J}$.

A Spring Is Stretched From 0.500 m0.500 \mathrm{~m}0.500 m To 0.800 m0.800 \mathrm{~m}0.800 m Assume the Unstretched Position Is

A Spring Is Stretched From $0.500 \mathrm{~m}$ To $0.800 \mathrm{~m}$ Assume the Unstretched Position Is