A $1.10 \mathrm{~kg}$ Hollow Steel Ball Is Submerged in Water $8.75 \mathrm{~N}$

A $1.10 \mathrm{~kg}$ hollow steel ball is submerged in water. Its weight in water is $8.75 \mathrm{~N}$ . The volume of the cavity inside the ball is (density of steel is $7,900 \mathrm{~kg} / \mathrm{m}^{3}$ )

A) $1.59 \times 10^{-5} \mathrm{~m}^{3}$ .
B) $6.79 \times 10^{-5} \mathrm{~m}^{3}$ .
C) $2.07 \times 10^{-4} \mathrm{~m}^{3}$ .
D) $1.39 \times 10^{-4} \mathrm{~m}^{3}$ .
E) $1.13 \times 10^{-4} \mathrm{~m}^{3}$