The pressure at what depth in seawater (density $1,025 \mathrm{~kg} / \mathrm{m}^{3}$ ) is equivalent to that at a depth of $10.0 \mathrm{~m}$ in fresh water (density $1,000 \mathrm{~kg} / \mathrm{m}^{3}$ )?
A) $9.76 \mathrm{~m}$
B) $10.3 \mathrm{~m}$
C) $9.81 \mathrm{~m}$
D) $10.2 \mathrm{~m}$

Question

Quizplus · Accepted Answer

The pressure at a certain depth in a fluid is given by $P = \rho gh$, where $\rho$ is the density of the fluid, $g$ is the acceleration due to gravity, and $h$ is the depth. To find the equivalent depth in seawater, we set the pressures equal: $1,000 \times 9.8 \times 10 = 1,025 \times 9.8 \times h$. Solving for $h$ gives $h = 9.76 \, \text{m}$.

The Pressure at What Depth in Seawater (Density 1,025 kg/m31,025 \mathrm{~kg} / \mathrm{m}^{3}1,025 kg/m3

The Pressure at What Depth in Seawater (Density $1,025 \mathrm{~kg} / \mathrm{m}^{3}$