Solve the variation problem.
-The distance that a spring is stretched by a hanging object varies directly as the mass of the object. If an object with a mass of 6 kg stretches a spring 30 cm, find the stretch when the object has a mass of 10 kg.
A) 6. 10 cm
B) 50 cm
C) 46 cm
D) 2 cm

Question

Quizplus · Accepted Answer

The distance stretched varies directly with the mass, so we use the formula $y = kx$, where $y$ is the distance stretched, $x$ is the mass, and $k$ is the constant of variation. Given that 30 cm corresponds to 6 kg, we find $k = 30/6 = 5$. For a mass of 10 kg, the stretch is $5 \times 10 = 50$ cm.

Solve the Variation Problem