Forty-nine percent of a population is homozygous dominant for a particular trait. According to the Hardy-Weinberg law, the gene frequency of this dominant allele will be

Question

Quizplus · Accepted Answer

In Hardy-Weinberg equilibrium, the frequency of the homozygous dominant genotype (AA) is represented as p^2, where p is the frequency of the dominant allele. Given that 49% (or 0.49) of the population is homozygous dominant, we have p^2 = 0.49. Taking the square root of both sides gives p = sqrt(0.49) = 0.7, indicating that the gene frequency of the dominant allele is 0.70.

Forty-Nine Percent of a Population Is Homozygous Dominant for a Particular